Решите систему уравнений { (y+1) (x-12) = 0 { (x-y+2) / (y-2) = 5

(y+1) (x-12) = 0

(x+y+2) / (y-2) = 5

(y+1) (x-12) = 0

x=y+2=5y-10

(y+1) (x-12) = 0

x=6y-12

(y+1) (6y-12-12) = 0

y=-1

y=4

x=6 * (-1) - 12

x=6*4-12

x=-18

x=12

x1=-19

y1=-1

x2=12

y2=4

(-1+1) * (-18-12) = 0

-18 - (-1) + 2/-1-2=5

(4+1) * (12-12) = 0

12-4+2/4-2=5

0=0

5=5

0=0

5=5

x1=-18

y1=-1

x2=12

y2=4