Найти f' (1)

f (x) = (2x-3) ^2 (x-1)

f (x) = (x+1) ^3 (x+2)

Question

Алгебра

Валерьич

9 августа, 12:28

Найти f' (1)

f (x) = (2x-3) ^2 (x-1)

f (x) = (x+1) ^3 (x+2)

+5

Ответы (1)

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Гога · Answer 1

F (x) = (2x-3) ^2 (x-1)

f (x) = (2*1-3) ^2 (1-1)

f (x) = (-1) ^2

f (x) = 1

f (x) = (x+1) ^3 (x+2)

f (x) = (1+1) ^3 (1+2)

f (x) = 2^3 * 3

f (x) = 8*3 = 24

Найти f' (1)f (x) = (2x-3) ^2 (x-1)f (x) = (x+1) ^3 (x+2)

Найти f' (1)

f (x) = (2x-3) ^2 (x-1)

f (x) = (x+1) ^3 (x+2)