1) - 2sin (x + π/4) = √6/2;

2) √2sin (2 / (x-1)) = 0

Question

Алгебра

Маргоша

5 ноября, 10:30

1) - 2sin (x + π/4) = √6/2;

2) √2sin (2 / (x-1)) = 0

+1

Ответы (1)

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Белла · Answer 1

1

-2sin (x + π/4) = √6/2

sin (x + π/4) = - √6/4

x + π/4 = (-1) ^ (k+1) arcsin√6/4+πk

x=-π/4 + (-1) ^ (k+1) arcsin√6/4+πk, k∈z

2

√2sin (2 / (x-1)) = 0

sin (2 / (x-1)) = 0

2 / (x-1) = πk

x-1=2/πk

x=1+2/πk, k∈z

1) - 2sin (x + π/4) = √6/2;2) √2sin (2 / (x-1)) = 0

1) - 2sin (x + π/4) = √6/2;

2) √2sin (2 / (x-1)) = 0