Решите систему уравнений! {10 - (9x-2y) = 18-4y} {2x-3 (1+y) = 2 (3x-y) } любым способом!

10 - (9x-2y) = 18-4y

2x-3 (1+y) = 2 (3x-y)

2x-3 (1+y) = 2 (3x-y)

2x-3-3y-6x+2y=0

-4x-3-y=0

y=-4x-3

10 - (9x-2y) = 18-4y

10-9x+2y-18+4y=0

-8-9x+6y=0

-8-9x+6 * (-4x-3) = 0

-8-9x-24x-18=0

-26-33x=0

x=-26/33

-4 * (-26/33) - 3-y=0

104/33-3-y=0

y=5/33