Помогите решить систему

{х+у=5

{х^3+у^3=35

буду очень благодарна

35 = x^3 + y^3 = (x+y) * (x^2 - xy + y^2) = W,

т. к. x+y=5, то y=5-x, и

W = 5 * (x^2 - xy + y^2) = 5 * (x^2 - x * (5-x) + (5-x) ^2) = 5 * (x^2 - 5x + x^2 + 25 - 10x + x^2) = 5 * (3*x^2 - 15x + 25) = 35,

3*x^2 - 15x + 25 = 35/5 = 7;

3*x^2 - 15x + 25 - 7=0;

3*x^2 - 15x + 18 = 0;

x^2 - 5x + 6 = 0;

D = 5^2 - 4*6 = 25 - 24 = 1;

x1 = (5-1) / 2 = 4/2 = 2;

x2 = (5+1) / 2 = 6/2 = 3;

1) x1 = 2, тогда y1 = 5-x = 5-2 = 3;

2) x2 = 3, тогда y2 = 5-x = 5-3 = 2.

Ответ. (2; 3), (3; 2).