Решите систему уравнений:

3 х+y=1

x+1/3 - y/5=2

J{3x+y=1

{x+1/3 - (y/5) = 2|*15

{3x+y=1|*3

{5x-3y=25

+{9x+3y=25

+{5x-3y=3

14x=28:14

x=2

3*2+y=1

y=1-6

y=-5

3x+y=1

x+1/3-y/5=2

y=1-3x

x-y/5=2-1/3

y=1-3x

(5x-y) / 5 = (6-1) / 3

y=1-3x

(5x - (1-3x)) / 5=5/3

y=1-3x

(5x-1+3x) / 5=5/3

y=1-3x

(8x-1) / 5=5/3 |*15

y=1-3x

3 * (8x-1) = 5*5

y=1-3x

24x-3=25

y=1-3x

24x=28 | : 24

y=1-3x

x=7/6

y=1-3*7/6

x=7/6

y=1-7/2

x=7/6

y = (2-7) / 2

x=7/6

y=-5/2

x=7/6