Найдите p (x) = p1 (x) + p2 (x), если p1 (x) = 3x^2+2x-1; p2 (x) = x^3-3x^2

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9 января, 02:52

Найдите p (x) = p1 (x) + p2 (x), если p1 (x) = 3x^2+2x-1; p2 (x) = x^3-3x^2

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Мариша · Answer 1

P (x) = p1 (x) - p2 (x) + 3p3 (x)

p1 (x) = 2x^2 - 5x,

p2 (x) = 3x^2 + 1,

p3 (x) = x - 2

p (x) = (2x^2-5x) - (3x^2+1) + 3 * (x-2) =

= 2x^2 - 5x - 3x^2 - 1 + 3x - 6 =

= (2x^2 - 3x^2) + (3x - 5x) - (1+6) =

= - x^2 - 2x - 5 =

= (-1) * (x^2 + 2x + 5) =

= (-1) * [ (x+2) ^2 + 1]