Помоги решить логарифмическое уравнение!

log0.8 (3x^2 + x + 4) = log0.8 (17x+1)

log4 (x-4) + log4 (x+4) = log4 (3x+2)

log3 (3x+5) + log3 (2x-5) = log3 (10x - 16)

Log0.8 (3x^2 + x + 4) = log0.8 (17x+1)

{17x+1>0⇒x>-1/17

{3x²+x+4>0⇒x∈R,

D=1-48=-47<0

x∈ (-1/17; ∞)

3x²+x+4=17x+1

3x²-16x+3=0

D=256-36=220

x1 = (16-2√55) / 6 U x2 = (16+2√55 (/2

log4 (x-4) + log4 (x+4) = log4 (3x+2)

{x-4>0⇒x>4

x+4>0⇒x>-4

{3x+2>0⇒x>-2/3

x∈ (4; ∞)

log (3) (x²-16) = log (4) (3x+2)

x²-16=3x+2

x²-3x-18=0

x1+x2=3 u x1*x2=-18

x1=-3 не удов усл

х2=6

log3 (3x+5) + log3 (2x-5) = log3 (10x - 16)

{3x+5>0⇒x>-5/3

{2x-5>0⇒x>2,5

{10x-16>0⇒x>1,6

x∈ (2,5; ∞)

log (3) [ (3x+5) (2x-5) ]=log (3) (10x-16)

6x²-15x+10x-25=10x-16

6x²-15x-9=0

2x²-5x-3=0

D=25+24=49

x1 = (5-7) / 4=-0,5 не удов усл

х2 = (5+7) / 4=3