Решите уравнение сos (х+П/6) = - 1/2

Question

Алгебра

Станислава

26 мая, 20:45

Решите уравнение сos (х+П/6) = - 1/2

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Ответы (2)

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Ирена · Answer 1

Сos (х+П/6) = - 1/2

х+π/6 = + - (π-π/6) + 2πn, n∈Z

x+π/6=+-5π/6 + 2πn, n∈Z

x=+-5π/6 - π/6 + 2πn, n∈Z

x1=5π/6-π/6+2πn, n∈Z x2=-5π/6-π/6+2πn, n∈Z

x1=2π/3+2πn, n∈Z x2=-π+2πn, n∈Z

Дика · Answer 2

сos (х+П/6) = - 1/2

x + π/6=2π/3+2πn x+π/6=-2π/3+2πn

x=2π/3-π/6+2πn x=-2π/3-π/6+2πn

x=π/2+2πn x=-5π/6+2πn