2cos (х-п/6) = корень3

Question

Алгебра

Лолия

4 июня, 19:23

2cos (х-п/6) = корень3

+3

Ответы (1)

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Ферктиста · Answer 1

2cos⁡ (x-π/6) = √3

cos⁡ (x-π/6) = √3/2

cos⁡ (x-π/6) = √3/2

cos⁡ (2π - (x-π/6)) = √3/2

x-π/6=arccos⁡ (√3/2)

cos⁡ (13π/6 - x) = √3/2

x - π/6=π/6

13π/6 - x=arccos⁡ (√3/2)

x - π/6=π/6 + 2kπ, k ∈ z

13π/6 - x = π/6

x = π/3+2πk, kϵz

13π/6 - x=π/6+2πk, kϵz

x = π/3+2πk, kϵz

x=2π-2kπ, kϵz

x = π/3+2πk, kϵz

x=0+2πk, kϵz

x = π/3+2πk, kϵz

x=2πk, kϵz