1) (14 х-1) (2+х) = (2 х-8) (7 х+1)

2) (х+10) (х-5) - (х-6) (х+3) = 16 решите уравнения

(14 х-1) (2+х) = (2 х-8) (7 х+1)

1. Раскроем скобки

(14 х-1) (2+х) = (2 х-8) (7 х+1)

(14 х-1) (2+х) - (2 х-8) (7 х+1) = 0

81x + 6 = 0

81x = - 6

x = - 6/81

x = - 1/9

2) (х+10) (х-5) - (х-6) (х+3) = 16

Аналогично раскроем скобки

8x - 32 = 16

8x = 48

x = 6