Найти корни уравнений:

1) 2x^2+x-1/2x-1=2

2) 5/x-2 + 1 = 14/x^2-4x+4

1) 2x^2+x-1/2x-1=2

2x^2+x-0,5x-1=2

2x^2+0,5x-1-2=0

2x^2+1/2x-3=0

D=0,25+3*4*2=0,25+24=24,25

x1 = (-1/2+_/24,25) / 4

x2 = (-1/2-_/24,25) / 4

2) (5 / (x-2)) + 1 = (14 / (x^2-4x+4))

x^2-4x+4 = (x-2) ^2

общий знаменатель: (х-2) ^2

5 * (x-2) + 1 * (x-2) ^2=14

5x-10+x^2-4x+4=14

5x-10+x^2-4x+4=14

x^2+x-20=0

D = (1) ^2+20*4=81

x1=-1+9/2=4

x2=-10/2=-5