sin (2x+п/2) = 1

cos (x/2-п/3) = 0

Question

Алгебра

Алексаха

29 апреля, 03:35

sin (2x+п/2) = 1

cos (x/2-п/3) = 0

+1

Ответы (1)

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Генриетта · Answer 1

Решение

1) sin (2x + π/2) = 1

cos2x = 1

2x = 2πk, k∈Z

x = πk, k∈Z

2) cos (x/2 - π/3) = 0

x/2 - π/3 = π/2 + πn, n∈Z

x/2 = π/2 + π/3 + πn, n∈Z

x/2 = 5π/6 + πn, n∈Z

x = 5π/3 + 2πn, n∈Z

sin (2x+п/2) = 1cos (x/2-п/3) = 0

sin (2x+п/2) = 1

cos (x/2-п/3) = 0