Разложите на множители: 2 (3-b) + 5 (b-3) ^2

2 (3 - b) + 5 (b - 3) ² = 6 - 2b + 5 (b² - 6b + 9) = 6 - 2b + 5b² - 30b + 45 =

= 5b² - 32b + 51 D = 1024 - 1020 = 4

b₁ = (-b + √D) / 2a = (32 + 2) / 10 = 3,4

b₂ = (-b - √D) / 2a = (32 - 2) / 10 = 3

5b² - 32b + 51 = 5 (b - 3,4) (b - 3) = (5b - 17) (b - 3)