Решить

sin (x+1) = sinx+sin1

Sin (x+1) = sinx+sin1;

2sin (x+1) / 2 * cos (x+1) / 2 = 2sin (x+1) / 2*cos (x-1) / 2;

sin (x+1) / 2 (cos (x+1) / 2 - cos (x-1) / 2) = 0;

-2sin (x+1) / 2*sin (x/2) * sin1/2 = 0;

-2sin1/2 ≠ 0;

[sin (x+1) / 2 = 0; sin (x/2) = 0.

[ (x+1) / 2 = πk; x/2 = πk.

[x = 2πk - 1; x = 2 πk, k∈Z.