Y = (x+1) arccos 3x^4 производную?

y' = (x+1) 'arccos (3x^4) + arccos' (3x^4) * (x+1) = arccos (3x^4) - (x+1) / (1+3x^8) (12x^3)

(u*v) ' = u'v + v'u;

(arccos (f (x))) ' = (-1 / (1+f (x) ^2)) * f' (x) ;

(3x^4) ' = 3*4x^ (4-1) = 12x^3;

(x+1) ' = x' + 1' = 1 + 0 = 1;