Решите уравнения (-5*-3) (2*-1) = 0

(-5x - 3) (2x - 1) = 0

-10x^2 + 5x - 6x + 3 = 0

-10x^2 - x + 3 = 0, * (-1)

10x^2 + x - 3 = 0

D = b^2 - 4ac,

(a = 10, b = 1, c = - 3)

D = 1 + 4*10*3 = 121 = 11^2

x1, x2 = (-b+-корень изD) / 2a

x1 = (-1 - 11) / 20 = - 0.6

x2 = (-1 + 11) / 20 = 0.5

ответ: x = - 0.6, x = 0.5