Log²2 (1-x) - 2 log2 (1-x) - 3=0 log5x+log (x-1) = 1 log4x+log8x=5

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Log²2 (1-x) - 2 log2 (1-x) - 3=0 замена log2 (1-x) = а 1-х>0 x<1

a ²-2a-3=0

D=4+12=16

a = (2+4) / 2=3 log2 (1-x) = 3 1-x=2³ 1-x=8 x=-7

a = (2-4) / 2=-1 log2 (1-x) = - 1 1-x=2⁻¹ 1-x=1/2 x=1/2

log₄x+log₈ x=5

log₂² x+log₂³ x=5

1/2 log₂ x + 1/3log₂ x = 5

5/6 log₂x = 5

log₂ x = 5*6/5

log₂ x = 6

x=2⁶=64