Arctg (x) = p/24 если х=√6-√3+√2-2

и

arctg (x) = p/12 если х = (√3-1) / (√3+1)

1) х=√6-√3 / (√2-2) = √3 (√2-1) - √2 (√2-1) =

(√2-1) (√3-√2)

tgπ/24 = (√2-1) (√3-√2)

2) x = (√3-1) / (√3+1) = (√3-1) ² / (3-1) = (3-2√3+1) / 2

= (4-2√3) / 2=2-√3

arctg (2-√3) = π/12

tgπ/12=2-√3

(1-cosπ/6) / sinπ/6 = (1-√3/2) / (1/2) =

(2-√3) : 1/2=2-√3