Решите уравнение

1) 3x^2-4x=0

2) x^3-x^2-x+1=0

1)

3x^2 - 4x = 0

x (3x - 4) = 0

x = 0;

3x - 4 = 0 = > 3x = 4 = > x = 4/3

Ответ

0; 4/3

2)

x^3 - x^2 - x + 1 = 0

x^2 (x - 1) - 1 (x - 1) = 0

(x - 1) (x^2 - 1) = 0

x - 1 = 0 = = > x = 1;

x^2 - 1 = 0 = > x^2 = 1 = = > x = ± 1

Ответ

- 1; 1