Дано уравнение |cosx| = - sqrt3 * sinx

1) сosx<0

x∈ (π/2+2πn; 3π/2+2πn, n∈z)

-cosx=-√3sinx

cosx-√3sinx=0

2 (1/2cosx-√3/2sinx) = 0

2cos (x+π/3) = 0

x+π/3=π/2+πn, n∈z

x=π/6+πn, n∈z

нет решения

2) сosx≥0

x∈[-π/2+2πn; π/2+2πn, n∈z]

cosx=-√3sinx

cos (x-π/3) = 0

x-π/3=π/2+πn

x=5π/6+πn, n∈z