Решите неравенство

-2x²-5x+3≤0

5x²-2x-3≤0

-2x^2 - 5x + 3 = 0;

D = b^2 - 4ac;

D = - 5^2 - 4 * (-2) * 3;

D = 25 + 24 = 49;

D > 0, два корня!

x1,2 = (-b ± √D) / 2a;

x1:x = (5 + 1) / 2*2;

x = 6/4;

x = 1 * (1/4) ;

x2:x = (5 - 1) / 2*2;

x = 4/4;

x = 1;

Ответ: 1 * (1/4) ; 1.

5x^2 - 2x - 3 = 0;

D = b^2 - 4ac;

D = - 2^2 - 4 * 5 * (-3) ;

D = 4 + 60 = 64;

D > 0, два корня!

x1,2 = (-b ± √D) / 2a;

x1:x = (2 + 8) / 2*5;

x = 10/10;

x = 1;

x2:x = (2 - 8) / 2*5;

x = - (6/10) ;

x = - (3/5) ;

Ответ: 1; - (3/5).