Log 2x-1 (2x-3) = log 2x-3 (2x-1)

ОДЗ

2x-1>0⇒x>1/2

2x-1≠1⇒x≠1

2x-3>0⇒x>3/2

2x-3≠1⇒x≠2

x∈ (1,5; 2) U (2; ∞)

log (2x-1) (2x-3) = 1/log (2x-1) (2x-3)

log² (2x-1) (2x-3) = 1

1) log (2x-1) (2x-3) = - 1

2x-3=1 / (2x-1)

(4x²-2x-6x+3-1) / (2x-1) = 0

4x²-8x+2=0

2x²-4x+1=0

D=16-8=8

x1 = (4-2√2) / 4=1-0,5√2 не удов усл

x2=1+0,5√2

2) log (2x-1) (2x-3) = 1

2x-3=2x-1

2x-2x=1+3

0=4

нет решения