Вычислите:

1) 64^1/2 2) 121^1/2 3) (243x 32) ^1/5 4) 9^8x25^7:225^6 5) - 150x128^1/7+35

6) (1/25) ^-6x3125^3/5x (5^-3) + 25^5/2x (1/5) ^3 7) (25^4) ^1/8

Question

Математика

Римма

4 октября, 19:37

Вычислите:

1) 64^1/2 2) 121^1/2 3) (243x 32) ^1/5 4) 9^8x25^7:225^6 5) - 150x128^1/7+35

6) (1/25) ^-6x3125^3/5x (5^-3) + 25^5/2x (1/5) ^3 7) (25^4) ^1/8

+3

Ответы (1)

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Юраня · Answer 1

1) 64¹/² = (8²) ¹/² = 8¹ = 8

2) 121¹/² = (11²) ¹/² = 11¹ = 11

3) (243 · 32) ¹/⁵ = (3⁵ * 2⁵) ¹/⁵ = (3⁵) ¹/⁵ * (2⁵) ¹/⁵ = 3 * 2 = 6

4) 9 ⁸ · 25 ⁷ : 225⁶ = 9*9⁷ · 25⁷ : 225⁶ = 9 · (9·25) ⁷ : (225) ⁶ =

= 9· (225) ⁷ : (225) ⁶ = 9 · 225⁷⁻⁶ = 9 · 225 = 2025

5) - 150 · 128 ¹/⁷ + 35 = - 150 · (2⁷) ¹/⁷ + 35 = - 150 * 2 + 35 =

= - 300 + 35 = - 265

6) (1/25) ⁻⁶ · 3125³/⁵ · 5 ⁻³ + 25 ⁵/² · (1/5) ³ =

= 25⁶ · (5⁵) ³/⁵ · (1/5) ³ + (5²) ⁵/² · (1/5) ³ =

= (5²) ⁶ · 5³ · (1/5) ³ + 5⁵ · (1/5) ³ =

= 5¹²⁺³ · (1/5) ³ + 5⁵ · (1/5) ³ =

= 5¹⁵ · (1/5) ³ + 5⁵ · (1/5) ³ =

= 5¹⁵⁻³ + 5⁵⁻³ =

= 5¹² + 5²

7) (25 ⁴) ¹/⁸ = (25) ⁴/⁸ = 25¹/² = (5²) ¹/² = 5

Вычислите:1) 64^1/2 2) 121^1/2 3) (243x 32) ^1/5 4) 9^8x25^7:225^6 5) - 150x128^1/7+356) (1/25) ^-6x3125^3/5x (5^-3) + 25^5/2x (1/5) ^3 7) (25^4) ^1/8

Вычислите:

1) 64^1/2 2) 121^1/2 3) (243x 32) ^1/5 4) 9^8x25^7:225^6 5) - 150x128^1/7+35

6) (1/25) ^-6x3125^3/5x (5^-3) + 25^5/2x (1/5) ^3 7) (25^4) ^1/8