Помогите решить sin (2x-3) = 0,5

sin (2x-3) = 0,5

sin (2x-3) = 1/2

sin (π - (2x-3)) = 1/2

2 х - 3 = arcsin (1/2)

sin (π - 2x + 3) = 1/2

2x-3 = π/6

π - 2x+3 = arcsin (1/2)

2x-3 = π/6 + 2k π

π - 2x + 3 = π/6

x = π/12 + 3/2 + k π

π - 2x + = π/6 + 2k π

x = π/12 + 3/2 + k π

x = 5 π/12 + 3/2 - k π

x = 5π/12 + 3/2 + kπ

x = 5π/12 + 3/2 + kπ

x = π/12 + 3/2 + kπ

x = 5π/12 + 3/2 + kπ

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