Log5^2 (25-x^2) - 3log5 (25-x^2) + 2>=0

ОДЗ (5-x) (5+x) ⇒x∈ (-5; 5)

log (5) (25-x²) = a

a²-3a+2≥0

a1+a2=3 U a1*a2=2⇒a1=1 U a2=2

a≤1⇒log (5) (25-x²) ≤1⇒25-x²≤5⇒ (20-x²) ≤0⇒ (2√5-x) (2√5+x) ≤0⇒x≤-2√5 U x≥2√5

a≥2⇒log (5) (25-x²) ≥2⇒25-x²≥25⇒x²≤0⇒x=0

x∈ (-5; -2√5] U [2√5; 5) U x=0