Помогите в решении уравнения 2/7x+3/7x=2 7/14, если можно то подробно

(x2-7x+3) ^2+10 (x2-7x+3) + 21=0

x2-7x+3=t

t2+10t+21=0

t12 = (-10+-корень (100-84)) / 2 = (-10+-4) / 2=-7 - 3

x2-7x+3=-3

x2-7x+6=0

x12 = (7+-корень (49-24)) / 2 = (7+-5) / 2=6 1

x2-7x+3=-7

x2-7x+10=0

x34 = (7+-коренб (49-40)) / 2 = (7+-3) / 2=5 2

x = 1 2 5 6

(x^2 - 7x + 3) ^2 + 10 (x^2 - 7x + 3) + 21 = 0

Пусть x^2 - 7x + 3 = t

t^2 + 10t + 21 = 0

D/4 = 25 - 21 = 4

t1 = - 5 + 2 = - 3

t2 = - 5 - 2 = - 7

Выполним обратную замену:

x^2 - 7x + 3 = - 3 или x^2 - 7x + 3 = - 7

x^2 - 7x + 6 = 0 x^2 - 7x + 10 = 0

D = 49 - 24 = 25 D = 49 - 40 = 9

x1 = (7+5) / 2 = 6 x3 = (7+3) / 2 = 5

x2 = (7-5) / 2 = 1 x4 = (7-3) / 2 = 2

Ответ: 1; 2; 5; 6. я думаю так