2^x-2^ (x-2) = 3

(4/9) ^x * (27/8) ^ (x-1) = 2/3

Question

Алгебра

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3 февраля, 21:29

2^x-2^ (x-2) = 3

(4/9) ^x * (27/8) ^ (x-1) = 2/3

+2

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Альбин · Answer 1

1) 2^x - 2^x / 2^2 = 3

2^x = a

a - a/4 = 3

4a - a = 12

3a=12

a=4

2^x=4

x=2

2) (2/3) ^2x * (2/3) ^ (-3x+3) = 2/3

(2/3) ^ (2x-3x+3) = 2/3

2x-3x+3=1

-x=-2

x=2

2^x-2^ (x-2) = 3(4/9) ^x * (27/8) ^ (x-1) = 2/3

2^x-2^ (x-2) = 3

(4/9) ^x * (27/8) ^ (x-1) = 2/3