Sin4x-sinx=0

Найти кони на промежутке

2sin (3x/2) cos (5x/2) = 0

sin (3x/2) = 0

3x/2=πk

x=2πk/3, k∈z

π≤2πk/3≤5π/2

6≤4k≤15

6/4≤k≤15/4

k=2 x=4π/3

k=3 x=2π

cos (5x/2) = 0

5x/2=π/2+πk

x=π/5+2πk/5

π≤π/5+2πk/5≤5π/2

10≤2+4k≤25

8≤4k≤23

2≤k≤23/4

k=2 x=π

k=3 x=7π/5

k=4 x=9π/5

k=5 x=11π/5