1) найдите g' (p/36) если g (x) = sin24x/cos12x

2) Найдите y' (5p/4), если y (x) = 9√2 sinx - 7 tgx

1

g (x) = sin24x/cos12x

g (x) = 2sin12x*cos12x/cos12x

g (x) = 2sin12x

g' (x) = 2*12*cos12x=24cos12x

g' (π/36) = 24cosπ/3=24*1/2=12

2

y (x) = 9√2sinx-7tgx

y' (x) = 9√2cosx-7/cos²x

y' (5π/4) = 9√2cos (5π/4) - 1/cos² (5π/4) = 9√2 * (-√2/2) - 7:1/2=-9-14=-23