Найти уравнение первообразной а) f (x) = x^3+2, A (-1:3)

б) f (x) = x+3 B (1; 2)

в) f (x) = 2+x^2 A (3; 1)

A) F (x) = x⁴/4 + 2x + C;

A (-1, 3)

3 = (-1) ⁴/4 + 2 * (-1) + C = 0.25 - 2 + C;

3 = - 1.75 + C = > C = 3 + 1.75 = 4.75;

б) F (x) = x²/2 + 3x + C;

B (1, 2)

2 = 1/2 + 3*1 + C;

C = 2 - 3.5 = - 1.5;

в) F (x) = 2x + x³/3 + C;

A (3, 1)

1 = 2*3 + 27/3 + C = 15 + C;

C = 1 - 15 = - 14;