Найдите производную функции f (x) = sin2x-cos3x

1) f (x) = sin2x-cos3x

cos (2x) d/dx [2x]+d/dx [-cos (3x) ]

cos (2x) (2 d/dx [x]) + d/dx [-cos (3x) ]

cos (2x) * 2+d/dx [-cos (3x) ]

2*cos (2x) + d/dx [-cos (3x) ]

2cos (2x) + d/dx [-cos (3x) ]

2cos (2x) - d/dx [cos (3x) ]

- (-sin (3x) d/dx [3x])

- (-sin (3x) (3 d/dx [x]))

2cos (2x) - (-sin (3x) (3*1))

2cos (2x) - (-sin (3x) * 3)

2cos (2x) - (-3sin (3x))

2cos (2x) + 3sin (3x)