1 + sinx * cos2x = sinx + cos2x

1+sinx (cos^2 x - sin^2 x) = sin x + cos^2 x - sin^2 x

1 + sin x cos^2 x-sin^3 x=sinx (1 - sinx) + cos^2 x

1 - sin^3 x - sin x (1-sinx) = cos^2 x - sin x*cos^2 x

1 - sin^3 x = cos^2 x (1-sinx) + sinx * (1-sin x)

(1-sin x) (1+sinx+sin^2 x) = (cos^2 x+sin x) (1-sin x)

1+sinx+sin^2 x = cos^2 x + sin x

1=cos 2x

2x=0

x=0

Ответ

x = 2pi * n; n прин z