6 * (b-3) = 10-2 * (b+2) и 83+5 * (y-3) = 3 * (8y-9)

Question

Математика

Савелий

16 июля, 21:47

6 * (b-3) = 10-2 * (b+2) и 83+5 * (y-3) = 3 * (8y-9)

+4

Ответы (2)

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Нефёд · Answer 1

6 * (b-3) = 10-2 * (b+2)

6b - 18 = 10 - 2b - 4

6b + 2b = 10 - 4 + 18

8b = 24

b = 3

83+5 * (y-3) = 3 * (8y-9)

83 + 5y - 15 = 24y - 27

5y - 24y = - 83 + 15 - 27

-19y = - 95

y = 5

Марин · Answer 2

6*b-18=10-2*b-4

6*b+2*b=6+18

8*6=24

b=3

83+5*y-15=24*y-27

19*y=68+27

y=95:19

y=5