Помогите решить уравнение

y''-10y'=x^2

1. y'' - 10y' = 0

k^2 - 10k = 0

k = 0, 10

y0 = C1 + C2*e^10x

2. y = ax^3 + bx^2 + cx

y'' - 10y' = 6ax + 2b - 30ax^2 - 20bx - 10c = x^2

-30a = 1 - - > a = - 1/30

6a - 20b = 0 - > b = - 1/100

2b - 10c = 0 - > c = - 1/500

y1 = - x^3/30 - x^2/100 - x/500

==>

y = C1 + C2*e^10x - x^3/30 - x^2/100 - x/500