Решить неравенство (x+3) / (x-2) >0 и найти область значений

(x+3) / (x-2) >0 | * (x-2)

(x+3) * (x-2) >0 * (x-2)

x²-2x+3x-6>0

x²+x-6>0

a=1 b=1 c=-6

x₁ = (-b-√ (b²-4ac)) / 2a=

= (-1-√ (1+24)) / (2*1) =

= (-1-√25) / 2=

= (-1-5) / 2=

=-6/2=

=-3

x₂ = (-b+√ (b²-4ac)) / 2a=

= (-1+√ (1+24)) / (2*1) =

= (-1+√25) / 2=

= (-1+5) / 2=

=4/2=

=2