3√2 (cos35-sin35) / cos100

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8 февраля, 08:29

3√2 (cos35-sin35) / cos100

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Даня · Answer 1

3√2 (cos35-sin35) / cos100=

=3√2 (sin (45-10) - sin (45+10)) / cos (90+10) =

=3√2 (sin (45) * cos (10) - sin (10) * cos (45) - sin (45) * cos (10) - sin (10) * cos (45)) / sin (10) =

=3√2 (-2*sin (10) * cos (45)) / sin (10) =

=3√2 (-2*cos (45)) = 3√2 (-2*√2/2) = - 6

Фрол · Answer 2

3√2 (cos35-cos55) / cos (90+10) = 3√2*2sin45sin10 / (-sin10) = - 3√2*2*√2/2=-6