4 1/3 : (5/6 + 0,25) И ВОТ Еще 3,6 • (7/12 + 1/9)

Помогите решить пример 4 целых 1/3 * (5/6+0.25) * 3,6 * (7/12+1/9) * (7/12-2/15) разделить 0,9 * (5/8-1/3) * 1 целая5/7

4_1/3 * (5/6+0.25) * 3,6 * (7/12+1/9) * (7/12-2/15) / (0,9 * (5/8-1/3) * 1_5/7) =

= (13/3) * (5/6+0.25) * 3,6 * (7/12+1/9) * (7/12-2/15) / (0,9 * (5/8-1/3) * (12/7)) =

(13/3) * (5/6+1/4) * (18/5) * (7/12+1/9) * (7/12-2/15) / (0,9 * (5/8-1/3) * (12/7)) =

= (13/3) * (13/12) * (18/5) * (25/36) * (27/60) / (0,9 * (7/2) * (1/7)) =

=13 * (13/4) * (1/4) * (1/2) / ((9/10) * (7/2) * (1/7)) =

= ((13*13*1*1) / (4*4*2)) / ((9*7*1) / (10*2*7)) =

= (169/32) / (63/140) =

= (169*140) / (32*63) =

= (169*35) / (8*63) =

= (169*5) / (8*9) =

=845/72 = 11_53/72 (11 целых и 53/72)

Если задание выглядит так:

(4_1/3) / (5/6+0.25) * 3,6 * (7/12+1/9) * (7/12-2/15) / (0,9 * (5/8-1/3) * 1_5/7) =

= (13/3) / (5/6+0.25) * 3,6 * (7/12+1/9) * (7/12-2/15) / (0,9 * (5/8-1/3) * (12/7)) = 10

4 1/3: (5/6+0,25) = 4

3,6 * (7/12+1/9) = 2 целых 1/2