1) (1-а) (2+0) - (2+а) (1-в) =

2) (9m-2n) (2m+n) - (6m+n) (3m-2n) =

Question

Алгебра

Васа

1 июня, 19:37

1) (1-а) (2+0) - (2+а) (1-в) =

2) (9m-2n) (2m+n) - (6m+n) (3m-2n) =

+3

Ответы (1)

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Борисыч · Answer 1

1)

(1 - a) * 2 - (2 + a) (1 - b) =

= 2 - 2a - (2 - 2b + a - ab) =

= 2 - 2a - 2 + 2b - a + ab =

= - 3a + 2b + ab

2)

18m^2 + 9mn - 4mn - 2n^2 - (18m^2 - 12mn + 3mn - 2n^2) =

= 18m^2 + 5mn - 2n^2 - (18m^2 - 9mn - 2n^2) =

= 18m^2 + 5mn - 2n^2 - 18m^2 + 9mn + 2n^2 =

= 14mn

1) (1-а) (2+0) - (2+а) (1-в) =2) (9m-2n) (2m+n) - (6m+n) (3m-2n) =

1) (1-а) (2+0) - (2+а) (1-в) =

2) (9m-2n) (2m+n) - (6m+n) (3m-2n) =