1) 0.9-0.6 (х-3) = 2 (0.2 х-1.3)

2) - 0.4 (3 х-1) + 8 (0.8 х-0.3) = 5 - (3.8 х+4)

3) 4/7 (0.56-4.2 у) + 0.4=5/13 (0.52-6.5 у)

Question

Алгебра

Николаха

25 января, 04:57

1) 0.9-0.6 (х-3) = 2 (0.2 х-1.3)

2) - 0.4 (3 х-1) + 8 (0.8 х-0.3) = 5 - (3.8 х+4)

3) 4/7 (0.56-4.2 у) + 0.4=5/13 (0.52-6.5 у)

+4

Ответы (1)

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Петрай · Answer 1

1) 0.9-0.6 х+1.8=0.4 х-2.6 - 0.6 х-0.4 х=-2.6-0.9-1.8

-х=-5.3 / • (-1)

х=5.3

2) - 1.2 х+0.4+6.4 х-2.4=19 х+20

-1.2 х+6.4 х-19 х=20-0.4+2.4

5.2 х=22

х=4.2

3) 4/3.92-29.4 у+0.4=5/6.76-84.5 у

29.4 у+84.5 у=0.7-1-0.4

113.9 у=-0.7

у=0.006

1) 0.9-0.6 (х-3) = 2 (0.2 х-1.3)2) - 0.4 (3 х-1) + 8 (0.8 х-0.3) = 5 - (3.8 х+4)3) 4/7 (0.56-4.2 у) + 0.4=5/13 (0.52-6.5 у)

1) 0.9-0.6 (х-3) = 2 (0.2 х-1.3)

2) - 0.4 (3 х-1) + 8 (0.8 х-0.3) = 5 - (3.8 х+4)

3) 4/7 (0.56-4.2 у) + 0.4=5/13 (0.52-6.5 у)