Log3 (5-4x) = Log3 (x-1)

Log3 (7-x) >1

log1/3 (3-5x) <-3

помогите решить неравенство?

Log₃ (5 - 4x) = log₃ (x - 1)

ОДЗ: 5 - 4x > 0, x < 5/4

x - 1 > 0, x > 1

ОДЗ: 1 < x < 5/4, 1 < x < 1,25

5 - 4x = x - 1

- 4x - x = - 1 - 5

-5x = - 6

x = 6/5

x = 1,2

2) log₃ (7 - x) > 1

ОДЗ: 7 - x > 0, x < 7

3 > 1

7 - x > 3

- x > 3 - 7

-x > - 4

x < 4

x ∈ (- ≈; 4)

3) log₁/₃ (3 - 5x) < - 3

0 < 1/3 < 1

3 - 5x > (1/3) ⁻³

-5x > 3³ - 3

- 5x > 27 - 3

- 5x > 24

x < - 4,8